1.每次合并两个，合并K次。
public ListNode mergeKLists(ListNode[] lists) {
ListNode ans = null;
for (int i = 0; i < lists.length; ++i) {
ans = mergeTwoLists(ans, lists[i]);
}
return ans;
}
public ListNode mergeTwoLists(ListNode a, ListNode b) {
if (a == null || b == null) {
return a != null ? a : b;
}
ListNode head = new ListNode(0);
ListNode tail = head, aPtr = a, bPtr = b;
while (aPtr != null && bPtr != null) {
if (aPtr.val < bPtr.val) {
tail.next = aPtr;
aPtr = aPtr.next;
} else {
tail.next = bPtr;
bPtr = bPtr.next;
}
tail = tail.next;
}
tail.next = (aPtr != null ? aPtr : bPtr);
return head.next;
}2.分治法，相邻的两两合并，每次合并链表个数减少一半。
public ListNode mergeKLists(ListNode[] lists) {
return merge(lists, 0, lists.length - 1);
}
public ListNode merge(ListNode[] lists, int l, int r) {
if (l == r) {
return lists[l];
}
if (l > r) {
return null;
}
int mid = (l + r) >> 1;
return mergeTwoLists(merge(lists, l, mid), merge(lists, mid + 1, r));
}
public ListNode mergeTwoLists(ListNode a, ListNode b) {
if (a == null || b == null) {
return a != null ? a : b;
}
ListNode head = new ListNode(0);
ListNode tail = head, aPtr = a, bPtr = b;
while (aPtr != null && bPtr != null) {
if (aPtr.val < bPtr.val) {
tail.next = aPtr;
aPtr = aPtr.next;
} else {
tail.next = bPtr;
bPtr = bPtr.next;
}
tail = tail.next;
}
tail.next = (aPtr != null ? aPtr : bPtr);
return head.next;
}
}
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23.合并K个升序链表
https://blog.51cto.com/pigeon/5452259
