要求:编写一个脚本读入一些整数，分别输出这些整数中奇数的个数和偶数的个数，并输出0的个数.
实现脚本如下:
#!/bin/bash
#charpter_8-12
declare -a arr2
echo "Please input some integer numbers seprated by SPACE:"
read -a arr2
counter_odd=0
counter_even=0
counter_0=0
for i in "${arr2[@]}"
do
if [[ i -ne 0 ]]
then
if [[ i%2 -eq 0 ]]
then
let counter_even+=1
else
let counter_odd+=1
fi
else
let counter_0+=1
fi
done
echo "偶数个数:$counter_even"
echo "奇数个数:$counter_odd"
echo "0的个数:$counter_0"
脚本的执行效果:
[root@localhost charpter8]# sh 8-12 Please input some integer numbers seprated by SPACE: 10 11 0 12 13 0 14 15 0 偶数个数:3 奇数个数:3 0的个数:3 [root@localhost charpter8]# sh 8-12 Please input some integer numbers seprated by SPACE: -12 -13 -14 0 12 13 14 15 0 17 偶数个数:4 奇数个数:4 0的个数:2 [root@localhost charpter8]#
可以看到准确的输出了结果.
