给定int[][] meetings,比如
{
{66, 70} 0号会议截止时间66,获得收益70
{25, 90} 1号会议截止时间25,获得收益90
{50, 30} 2号会议截止时间50,获得收益30
}
一开始的时间是0,任何会议都持续10的时间,但是一个会议一定要在该会议截止时间之前开始,
只有一个会议室,任何会议不能共用会议室,一旦一个会议被正确安排,将获得这个会议的收益。
请返回最大的收益。
按截止时间从小到大排序,小根堆。
代码用golang编写。代码如下:
package main
import (
"fmt"
"sort"
)
func main() {
meetings := [][]int{{6, 20}, {9, 50}, {13, 42}}
ret := maxScore1(meetings)
fmt.Println(ret)
ret = maxScore2(meetings)
fmt.Println(ret)
}
func maxScore1(meetings [][]int) int {
//Arrays.sort(meetings, (a, b) -> a[0] - b[0]);
sort.Slice(meetings, func(i, j int) bool {
return meetings[i][0] < meetings[j][0]
})
//int[][] path = new int[meetings.length][];
path0 := make([][]int, len(meetings))
for i := 0; i < len(meetings); i++ {
path0[i] = make([]int, 2)
}
size := 0
return process1(meetings, 0, path0, size)
}
func process1(meetings [][]int, index int, path0 [][]int, size int) int {
if index == len(meetings) {
time := 0
ans := 0
for i := 0; i < size; i++ {
if time+10 <= path0[i][0] {
ans += path0[i][1]
time += 10
} else {
return 0
}
}
return ans
}
p1 := process1(meetings, index+1, path0, size)
path0[size] = meetings[index]
p2 := process1(meetings, index+1, path0, size+1)
// path[size] = null;
return getMax(p1, p2)
}
func getMax(a, b int) int {
if a > b {
return a
} else {
return b
}
}
func maxScore2(meetings [][]int) int {
sort.Slice(meetings, func(i, j int) bool {
return meetings[i][0] < meetings[j][0]
})
heap := make([]int, 0)
time := 0
// 已经把所有会议,按照截止时间,从小到大,排序了!
// 截止时间一样的,谁排前谁排后,无所谓
for i := 0; i < len(meetings); i++ {
if time+10 <= meetings[i][0] {
heap = append(heap, meetings[i][1])
sort.Slice(heap, func(i, j int) bool {
return heap[i] < heap[j]
})
time += 10
} else {
if len(heap) > 0 && heap[0] < meetings[i][1] {
heap[0] = meetings[i][1]
sort.Slice(heap, func(i, j int) bool {
return heap[i] < heap[j]
})
}
}
}
ans := 0
for len(heap) > 0 {
ans += heap[0]
heap = heap[1:]
sort.Slice(heap, func(i, j int) bool {
return heap[i] < heap[j]
})
}
return ans
}
执行结果如下: